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3x^2-5x-3=-3.6x+3
We move all terms to the left:
3x^2-5x-3-(-3.6x+3)=0
We get rid of parentheses
3x^2-5x+3.6x-3-3=0
We add all the numbers together, and all the variables
3x^2-1.4x-6=0
a = 3; b = -1.4; c = -6;
Δ = b2-4ac
Δ = -1.42-4·3·(-6)
Δ = 73.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.4)-\sqrt{73.96}}{2*3}=\frac{1.4-\sqrt{73.96}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.4)+\sqrt{73.96}}{2*3}=\frac{1.4+\sqrt{73.96}}{6} $
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